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The current is formed by the regular directional movement of the free charges in the conductor under the action of the electric field force.

According to Joule's law Q=I2Rt, it can be concluded that if 100A current is output per second, then there is Q=10000×R, which is 10KA current.

Under normal circumstances, when the human body is in contact with the current, when the current is 0.5 ~ 1mA, people will feel numbness or pain in the fingers and wrists.

When the human body is in contact with the electric current, when the electric current increases to 8-10mA, the acupuncture and pain sensations will increase, and convulsions will occur to grasp the charged body, but after all, the charged body will be able to get rid of.

But when the human body is in contact with the current, when the current reaches 20-30mA, it will quickly paralyze the person and cannot get rid of the charged body, and the blood pressure will rise and it will be difficult to breathe.

When the human body is in contact with the electric current, when the electric current is 50mA, the breathing will be paralyzed, the heart will start to vibrate, and it will be fatal after a few seconds.

The greater the current passing through the human body, the stronger the physiological response of the human body, the more serious the pathological state, and the shorter the fatal time.

And it is known that 1KA=1000A, 1A=1000mA...

It is conceivable what will happen after the 10,000A current enters the human body.

But the premise is that R is not air, and when R is air, the air resistivity is infinite, and in the case of arc discharge and gas ionization, the 10,000A current will disappear like a drop of fresh water entering the sea.

The electronic weekly cycle fades, which solves this problem.

It mixes αβ energy and electrons together and emits it, and it can absorb 0.001 degrees of αβ energy and 1A current in the energy system per second, with a maximum output of 30KL?.

These absorbed αβ energy and current will enter the accelerator tube along the superconductor, circulate for 1 week (168 seconds), mix into 1L? Ash energy, and then enter the accelerator launcher to launch.

But it doesn't mean that 0.001ав+1I is equal to 1L? This formula will hold.

(ав is the αβ symbol, I is the current symbol)

And the correct formula should be:

△=(x)ав⊕(c)I.

t△?? =(d)?

(x), (c) (d) are unknowns

⊕ is to stir, to mix.

t is time, which is known to be 168 seconds.

?? stands for unknown.

And the process of this formula is tortuous and long. Zhou Wenwen believes that his third grade level will definitely not be able to supplement this formula. When he sees Iron Man, he can talk to him.

But as the saying goes, practice brings true knowledge, Zhou Wenwen can try 1L unit? Ash energy, how powerful is it.

Thinking of this, Zhou Wenwen's interest suddenly increased. He pressed the button of the armor on his left hand to take over the αβ electron absorption cycle conversion and emission? Ash energy 0.1 system, called up 3 degrees of αβ energy and 10A current, and quickly introduced it into the acceleration tube, circulating flow .

The time setting is to fire after the time reaches 1 second.

So after more than 2 minutes, that is, 168 seconds and 1 second later, a white energy beam shot out from the mouth of the electronic cycle device and hit the tail of the pickup truck 5 (5.1) meters away from Zhou Wenwen within 3 (3.02 seconds). armor sheet.

The tail armor of the pickup immediately left the tail of the pickup, and flew more than 50 meters within 6 (6.72) seconds before landing. According to the surveying and mapping of hunters, it was 57.21 meters.

After getting the value, Zhou Wenwen began to calculate, first according to the formula t△?? =(d)? This first value formula will yield:

1×(3ав+10A)?? =(d)? This second value formula, in view of "0.001 degree ав+1A is equal to 1L?", import the second value formula and solve it to get:

1×3+1×10?? +2.997ав=30L?∝2.997ав.

∝ stands for surplus, parcel.

It is known that Q=I2Rt, and the unit of Q is J, that is, Joule, which is the unit of energy and work. 1 Joule of energy is equal to the work done by the action point of 1 Newton moving a distance of 1 meter in the direction of the force.

Then substituting 30L?∝2.997ав into the formula of I2R, the third value formula of Q=30L?∝2.997ав×t will be obtained.

In view of the fact that the tail armor of the pickup truck flew out 57.21 meters, import the third value formula and solve it to get:

57.21(J)Q=30(L)∝2.997(degree) ав×t is the fourth value formula.

It is also known that the time for the pickup truck tail armor to fly out is 6.72, and the fourth value formula is imported to solve it and we can get:

57.21(J)=30(L)∝2.997(degree) ав×6.72(s)

Simplify to get:

8.51339286(J)=4.46428571(L)∝0.445982143(degree) ав×1(s) This fifth value formula.

So what is the use of this 5th value formula? Is it correct?

Zhou Wenwen didn't know the answer, but he knew that this fifth value formula could be used as a comparison~www.wuxiaspot.com~ Zhou Wenwen took a deep breath and pressed the button of the left arm armor again to take over the absorption of αβ electrons Circular conversion launch? Ash energy 0.1 system, transfer 15 degrees αβ energy and 18A current, and introduce it into the acceleration tube, circulating flow.

If the time is still set, it will be launched after the time reaches 1 second.

In this way, after 168 seconds and 1 second, a not thick white energy beam shot out from the nozzle of the electronic cycle device with a bang, and hit the front of the pickup straight, and then an unexpected thing happened. .

The front of the pickup did not fly out like the rear armor of the pickup, but melted a small hole and exploded immediately. Obviously, the energy beam penetrated the oil pipe of the front of the pickup, and the high temperature ignited the gasoline. produce an explosion.

So how to calculate this second example?

Zhou Wenwen was lost in thought.

Zhou Wenwen knows that under normal atmospheric pressure, the spontaneous ignition point of gasoline is 427°C.

However, gasoline volatilizes quickly, and gasoline vapor is easily ignited when mixed with air, which will also cause the flash point of gasoline to be lower than about 28°. Generally, the lower the flash point, the higher the auto-ignition point.

The flash point is the temperature at which the oil can flash when it is heated to a certain temperature when it encounters an open flame, and the auto-ignition point is the temperature at which the oil comes into contact with enough air (oxygen) to burn when it reaches a certain temperature.

To be on the safe side, Zhou Wenwen preliminarily estimated that after the energy beam penetrated the oil pipe, when the gasoline and the air were fused, the energy beam with a surface temperature of 20 degrees extinguished the gasoline and eventually exploded.

Apart from gasoline, the key now is the energy beam with a surface temperature of 20 degrees.

And this involves the specific heat capacity.

Chapter 25 Predicting the Seventh-Valued Polynomial Formula